9x^2-7x+7=-1+10x

Solution for 9x^2-7x+7=-1+10x equation:

9x^2-7x+7=-1+10x

We move all terms to the left:

9x^2-7x+7-(-1+10x)=0

We add all the numbers together, and all the variables

9x^2-7x-(10x-1)+7=0

We get rid of parentheses

9x^2-7x-10x+1+7=0

We add all the numbers together, and all the variables

9x^2-17x+8=0

a = 9; b = -17; c = +8;
Δ = b2-4ac
Δ = -172-4·9·8
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*9}=\frac{16}{18}
=8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*9}=\frac{18}{18}
=1
$